I've been seeing a lot about this 100Ah / 1kW rule of thumb for GTI's having battery banks. I'd like to tell about the project I'm working on, and I would appreciate it if somebody would explain the necessity of using 600Ah of battery with the XW6048.
We are developing a 5kW fuel-cell power supply which needs to run continuously. Rather than load it with a $15k load bank and do nothing more than toss the energy away, we would like to tie the output into either our 120VAC or 240VAC line here in the building (don't worry, we plan to bring an electrician in).
Thus, the XW6048, which is the only GTI I can find which can work with the DC voltage range we need (we can't build a multi-100V system), and it also has a dynamically settable output current limit, which will be useful for controlling the inverter's behavior for testing purposes. I've checked with Outback, but they don't have such a feature, at least not one that can be set dynamically (that's what customer support said anyways).
So, my questions:
(1) If I can guarantee 5kW of power into the GTI at all times from our power supply, do I really need 500Ah or more of battery capacity?
(2) Does anyone know of an analysis from which this 100Ah / 1kW figure comes from, or is this purely empirical and best-practice based?
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The reason I ask these questions is that I've been trying to do a simple (simplistic?) analysis myself. From what I understand, the current input waveform of your typical true sine wave inverter is a sine-squared waveform, and the amplitude of the waveform is basically reflected back from the load. I know this from talking with the folks over at Zahn Inc., who make a lot of different converters. The way it was explained to me is on the principle of power-in = power-out. You take your peak output current (for a 2.5kW / 120VAC load, this would be sqrt(2) * 120V / (120V^2 / 2.5kW) ~=30A) and multiply it by your peak output voltage (sqrt(2) * 120V) over your worst-case (minimum) input voltage (say, 27V). This would be a peak input current of 185A, not including inefficiencies (example taken from
http://www.zahninc.com/documents/IM220c.pdf). Ergo, the input current waveform to something like the XW6048 would probably not be terribly different.
Now, if I understand correctly, the battery bank attached to the XW6048 acts as a charge storage device, not only for backup power, but it also takes the brunt of the AC currents being pulled by the GTI. Thus, if the GTI is pulling a sine-squared current waveform of large magnitude, and I subtract from the waveform the current being sourced by our 5kW power supply, the resulting waveform should be the battery current waveform.
If I assume a constant 5kW, 44V in (worst-case), what I find is that the total current waveform pulled in should be Iin(t) = 227A * sin^2(2*PI*F*t), where F = 60Hz. This is a sinusoidal waveform having a 120Hz frequency, which sounds similar to what SG is talking about here:
http://www.wind-sun.com/ForumVB/showthread.php?t=11709. (Post #7)
Next, at 5kW, 44V in, the DC current into the GTI is 5kW / 44V ~= 114A.
Thus, the battery current waveform should be Iin(t) = 227A * sin^2(2*PI*F*t) - 114A. If you integrate under this waveform, you get 0A, which is what you would expect for an AC battery current. Anything != 0 would imply a constant charge or discharge of the battery with some DC current.
Whew. Anyways, if you take the RMS of this current waveform, you get about 57ARMS, and a peak battery current (charge OR discharge) of ~114A.
The rest of the discussion assumes that I've not misunderstood something so far about how the GTI functions.
Now, what is the important factor here? Is it the repetitive > 100A charge and discharge of the battery bank, or is it the RMS current, which from what I understand is what actually generates the heat? The reason I ask is that most of the figures I run across for battery impedances are in the mOhm range. Yet even if my battery pack had an impedance of 50-mOhms, the RMS current would cause ~160W of heating in the packs. 160W dissipated over four packs doesn't sound like a lot for their size, but maybe it is? Possibly more important would be the voltage swing of the bank: 50-mOhm * 57ARMS = 2.85VRMS, which may be too much of a swing for a typical GTI.
What I'd like to know is if my analysis relates in any way to the real world of battery bank sizing. Obviously, a higher capacity bank would imply a lower battery impedance (right?), which would mitigate heating and voltage ripple. I am thinking that the periodic high-current charge / discharge plays a role also, in particular because there are limits to charge rates which are healthy for the bank (C/8?). If I want to ripple-charge the bank with a 114A-peak current every half-cycle there might be some issues beyond heating.
I'm kinda new to this stuff, so please be patient.
Regards,
Tele